Abstract
Hybridization in aromatic molecules plays an important role in determining their electron transport properties. When an sp2 bonded aromatic ring hybridizes with a carbon pair in either sp3, sp2, or sp form, only sp2 and sp result in a delocalized state across the whole molecule, opening a channel for transport. At the same time negative differential resistance (NDR) is found only in the sp2 and sp cases. An energy alignment scheme is adopted to elucidate the NDR process. This is constructed by comparing the positions of frontier molecular levels and the states of leads. It is revealed that the alignment between lead states located around the Fermi energy with the lowest unoccupied molecular orbital of the central molecule is the main cause of the NDR. © 2008 American Institute of Physics.
| Original language | English |
|---|---|
| Article number | 74710 |
| Journal | Journal of Chemical Physics |
| Volume | 129 |
| Issue number | 7 |
| DOIs | |
| Publication status | Published - 2008 |
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